Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

The problem is 
how many people must attend the third show so that the average attendance for three shows is 3000? And the other show attendance numbers are 2580, and 2920

Sagot :

luana
[tex]average=\frac{sum\ of\ attendance}{amount\ of\ shows}\\\\ average=3000\\\\ 3000=\frac{2580+2920+third\ show}{3}\ \ \ |*3\\ 9000=2580+2920+third\ show\\ 9000=5500+third\ show\ \ \ |Subtract\ 5500\\ 3500=third\ show\\\\ \textbf{3500\ people\ must\ attend\ the\ third\ show.} [/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.