miymiy1737
Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.


H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?
a. ±i√3
b. ±i
c. ±2
d. ±1
e. ±1, ±i

Sagot :

[tex]H(x)=x^2+1;\ K(x)=-x^2+4\\\\K(H)=K(x^2+1)=-(x^2+1)^2+4=0\\\\(x^2+1)^2=4\iff x^2+1=\pm\sqrt4\\\\x^2+1=-2\ or\ x^2+1=2\ \ \ \ |subtract\ 1\ from\ both\ sides\\\\x^2=-3\ or\ x^2=1\\\\\boxed{x=\pm i\sqrt3\ or\ x=\pm1}[/tex]
View image Аноним
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.