At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
[tex]2t^3+8t^2-24t=0\\2t(t^2+4t-12)=0\\2t=0\ \vee\ t^2+4t-12=0[/tex]
[tex]t^2+4t-12=0\\a=1\ ;\ b=4\ ;\ c=-12\\\Delta=b^2-4ac\\\Delta=4^2-4\cdot1\cdot(-12)=16+48=64\\\sqrt\Delta=\sqrt{64}[/tex]
[tex]t_1=\frac{-b-\sqrt\Delta}{2a}\ \vee\ t_2=\frac{-b+\sqrt\Delta}{2a}\\t_1=\frac{-4-8}{2\cdot1}\ \vee\ t_2=\frac{-4+8}{2\cdot1}\\t_1=\frac{-12}{2}\ \vee\ t_2=\frac42\\t_1=-6\ \vee\ t_2=2[/tex]
[tex]2t(t^2+4t-12)=0\\2t(t+6)(t-2)=0[/tex]
[tex]t^2+4t-12=0\\a=1\ ;\ b=4\ ;\ c=-12\\\Delta=b^2-4ac\\\Delta=4^2-4\cdot1\cdot(-12)=16+48=64\\\sqrt\Delta=\sqrt{64}[/tex]
[tex]t_1=\frac{-b-\sqrt\Delta}{2a}\ \vee\ t_2=\frac{-b+\sqrt\Delta}{2a}\\t_1=\frac{-4-8}{2\cdot1}\ \vee\ t_2=\frac{-4+8}{2\cdot1}\\t_1=\frac{-12}{2}\ \vee\ t_2=\frac42\\t_1=-6\ \vee\ t_2=2[/tex]
[tex]2t(t^2+4t-12)=0\\2t(t+6)(t-2)=0[/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.