To determine the cost per player of a group hitting lesson when there are 2, 5, and 8 players in the group, we need to evaluate the given formula [tex]\( C(x) = \frac{40 + 4x}{x} \)[/tex] for [tex]\( x = 2 \)[/tex], [tex]\( x = 5 \)[/tex], and [tex]\( x = 8 \)[/tex].
a) Determine the cost per player for different group sizes:
1. When [tex]\( x = 2 \)[/tex]:
[tex]\[
C(2) = \frac{40 + 4 \cdot 2}{2} = \frac{40 + 8}{2} = \frac{48}{2} = 24.0
\][/tex]
So, the cost per player when there are 2 players in the group is \[tex]$24.00.
2. When \( x = 5 \):
\[
C(5) = \frac{40 + 4 \cdot 5}{5} = \frac{40 + 20}{5} = \frac{60}{5} = 12.0
\]
So, the cost per player when there are 5 players in the group is \$[/tex]12.00.
3. When [tex]\( x = 8 \)[/tex]:
[tex]\[
C(8) = \frac{40 + 4 \cdot 8}{8} = \frac{40 + 32}{8} = \frac{72}{8} = 9.0
\][/tex]
So, the cost per player when there are 8 players in the group is \[tex]$9.00.
Thus, the cost per player of a group hitting lesson when there are:
- 2 players in the group is \$[/tex]24.00,
- 5 players in the group is \[tex]$12.00,
- 8 players in the group is \$[/tex]9.00.
