Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

I am getting 223g of C6H6. I understand the way this problem was solved, however, the teacher is giving a different equation for us to use. The equation is:

Amount Given x (1 mol given/molar mass) x ((y) mol sought/(x) mol given) x (molar mass/1 mol sought) = Answer

x and y are coefficients of the given substance from balanced equation.
Molar mass can be replaced with particles and L if needed based on the question

I am getting very different answers and not sure what next.

Sagot :

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.