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[tex]\displaystyle\\if\ \ \begin{cases} a^3-b^2+c^6=28 \\ \dfrac{a}{9}+\dfrac{b}{6} +\dfrac{c^3}{3}=11 \\ a^2-b+4c=110 \end{cases}\\\\\\a^2+b^2+c^2=?[/tex]

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