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If ZR and ZT are supplementary angles, mZR = (6X - 4)', and mZT= (2x + 16), find mZT?

If ZR And ZT Are Supplementary Angles MZR 6X 4 And MZT 2x 16 Find MZT class=

Sagot :

First we will draw the angles for better understanding

To find JML we will use the supplementary angles

[tex]\begin{gathered} \text{JML}=KJ-\text{LMK} \\ \text{JML}=180º-154º \\ \text{JML}=26º \end{gathered}[/tex]

To find NMK we will use the supplementary angles again becase LN=180º

[tex]\begin{gathered} LN=180º \\ \text{NMK}=LN-\text{LMK} \\ \text{NMK}=180º-154º \\ \text{NMK}=26º \end{gathered}[/tex]

finally we use the complementary angles to find PMN

[tex]\begin{gathered} \text{PMN}=90º-\text{NMK} \\ \text{PMN}=64º \end{gathered}[/tex]

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