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Alexandra has 36 coins valued at $6.00. She has only nickels and quarters. Which equation can be used to solve for the number of nickels, n?

A. 0.05n + 0.25(36 – n) = 6
B. 0.05n + 0.25(36 – n) = 36
C. n + 0.05 = 0.05n
D. n + (36 – n) = 36

Alexandra Has 36 Coins Valued At 600 She Has Only Nickels And Quarters Which Equation Can Be Used To Solve For The Number Of Nickels N A 005n 02536 N 6 B 005n 0 class=

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