The equation x^2-px+p+3=0 has real roots. Find the range of values that p can take. (3 marks)
Like I have worked out the discriminant (a=1, b=-p and c=(p+3)) and but I really do not know where to go from there.

Question

04-10-2022
Mathematics

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The equation x^2-px+p+3=0 has real roots. Find the range of values that p can take. (3 marks)
Like I have worked out the discriminant (a=1, b=-p and c=(p+3)) and but I really do not know where to go from there.

Sagot :

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