On réalise l'électrolyse d'une solution de sulfate de cuivre avec deux électrodes
de cuivre. L'intensité du courant est constante pendant la durée l'électrolyse et vaut
1.3 A. La perte de masse de l'anode est de 270 mg.
1)
Calculer la quantité d'électricité traversant le circuit.
Déterminer la durée de passage du courant.
2)
Pour le cuivre: A = 63.4; n = 2

Comment je dois résoudre le numéro 1) et 2)?

Question

03-10-2022
Physics

Answered

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On réalise l'électrolyse d'une solution de sulfate de cuivre avec deux électrodes
de cuivre. L'intensité du courant est constante pendant la durée l'électrolyse et vaut
1.3 A. La perte de masse de l'anode est de 270 mg.
1)
Calculer la quantité d'électricité traversant le circuit.
Déterminer la durée de passage du courant.
2)
Pour le cuivre: A = 63.4; n = 2

Comment je dois résoudre le numéro 1) et 2)?

Sagot :

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