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Find the area of ABCD

Find The Area Of ABCD class=

Sagot :

Answer:

Applying Heron's Formula

[tex]s=\frac{2.89+4.3+6.81}{2}[/tex]

[tex]s_1=7[/tex]

[tex]A_1=\sqrt{7(7-2.89)(7-4.3)(7-6.81)}[/tex]

[tex]A_1=10.56[/tex]

Now, [tex]s_2=\frac{6.81+8.59+7.58}{2}[/tex]

[tex]s_2=11.49[/tex]

[tex]A_2=\sqrt{11.49(11.49-6.81)(11.49-8.59)(11.49-7.59)}[/tex]

[tex]A_2=24.69[/tex]

Total Area:

[tex]10.56+24.69[/tex]

[tex]=35.25[/tex]

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