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Sagot :
Answer:
a) 67.6% of students is expected to pass the course
b) 0.9112 = 91.12% probability that he/she attended classes on Fridays
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
a. What percentage of students is expected to pass the course?
88% of 70%(attended class)
20% of 100 - 70 = 30%(did not attend class). So
[tex]p = 0.88*0.7 + 0.2*0.3 = 0.676[/tex]
0.676*100% = 67.6%
67.6% of students is expected to pass the course.
b. Given that a person passes the course, what is the probability that he/she attended classes on Fridays?
Here, we use conditional probability:
Event A: Passed the course
Event B: Attended classes on Fridays.
67.6% of students is expected to pass the course.
This means that [tex]P(A) = 0.676[/tex]
Probability that passed and attended classes on Friday.
88% of 70%
This means that:
[tex]P(A \cap B) = 0.88*0.7 = 0.616[/tex]
Then
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.616}{0.676} = 0.9112[/tex]
0.9112 = 91.12% probability that he/she attended classes on Fridays
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