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Sagot :
The four consecutive even integers will be expressed as
[tex]n \\ n+2 \\ n+4 \\ n+6[/tex]
So, we have to add them up and simplify the equation made.
[tex]n+n+2+n+4+n+6=244 \\ 4n+12=244 \\ 4n+(12-12)=(244-12) \\ 4n=232 \\ \frac{4n}{4}= \frac{232}{4} \\ n=58 [/tex]
So, you just substitute 58 into the numbers
[tex]n=58 \\ n+2=58+2=60 \\ n+4=58+4=62 \\ n+6=58+6=64[/tex]
The four consecutive even integers are 58, 60, 62 and 64.
[tex]n \\ n+2 \\ n+4 \\ n+6[/tex]
So, we have to add them up and simplify the equation made.
[tex]n+n+2+n+4+n+6=244 \\ 4n+12=244 \\ 4n+(12-12)=(244-12) \\ 4n=232 \\ \frac{4n}{4}= \frac{232}{4} \\ n=58 [/tex]
So, you just substitute 58 into the numbers
[tex]n=58 \\ n+2=58+2=60 \\ n+4=58+4=62 \\ n+6=58+6=64[/tex]
The four consecutive even integers are 58, 60, 62 and 64.
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